891804ae37
Signals, if they carry the same datatype, can be chained simply with `signal.connect(othersignal)` without the need to use a `lambda` expression and `emit()` TabWidget: Fix error because the `exit_app` signal was called directly
36 lines
1.3 KiB
Python
36 lines
1.3 KiB
Python
import webbrowser
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from PyQt5.QtCore import pyqtSignal
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from PyQt5.QtWidgets import QWidget, QVBoxLayout, QMessageBox, QLabel, QPushButton
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from rare.shared import LegendaryCoreSingleton, GlobalSignalsSingleton
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from rare.utils.misc import icon
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class AccountWidget(QWidget):
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logout: pyqtSignal = pyqtSignal()
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def __init__(self, parent):
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super(AccountWidget, self).__init__(parent=parent)
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self.core = LegendaryCoreSingleton()
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self.signals = GlobalSignalsSingleton()
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username = self.core.lgd.userdata.get("display_name")
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if not username:
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username = "Offline"
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self.open_browser = QPushButton(icon("fa.external-link"), self.tr("Account settings"))
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self.open_browser.clicked.connect(
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lambda: webbrowser.open(
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"https://www.epicgames.com/account/personal?productName=epicgames"
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)
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)
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self.logout_button = QPushButton(self.tr("Logout"))
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self.logout_button.clicked.connect(self.logout)
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layout = QVBoxLayout(self)
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layout.addWidget(QLabel(self.tr("Account")))
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layout.addWidget(QLabel(self.tr("Logged in as <b>{}</b>").format(username)))
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layout.addWidget(self.open_browser)
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layout.addWidget(self.logout_button)
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