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Code Issues Releases Wiki Activity

Correct how to check if a channel is online

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This commit is contained in:
Phxntxm 2017-03-12 21:56:24 -05:00
parent e0534d1d5b
commit a88ee2972b
1 changed files with 3 additions and 3 deletions
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6
cogs/picarto.py
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@ -32,10 +32,10 @@ class Picarto:
self.online_channels = await utils.request(url, payload=payload)
def channel_online(self, channel):
# online_channels is the dictionary of all users online currently
# And channel is the name we are checking against that
# Channel is the name we are checking against that
# This creates a list of all users that match this channel name (should only ever be 1)
# And returns True as long as it is more than 0
channel = re.search("(?<=picarto.tv/)(.*)", channel).group(1)
matches = [stream for stream in self.online_channels if stream['channel_name'].lower() == channel.lower()]
return len(matches) > 0
@ -50,7 +50,7 @@ class Picarto:
m_id = int(data['member_id'])
url = data['picarto_url']
# Check if they are online
online = await self.channel_online(url)
online = self.channel_online(url)
# If they're currently online, but saved as not then we'll send our notification
if online and data['live'] == 0:
for s_id in data['servers']: