/* * Greenshot - a free and open source screenshot tool * Copyright (C) 2007-2015 Thomas Braun, Jens Klingen, Robin Krom * * For more information see: http://getgreenshot.org/ * The Greenshot project is hosted on Sourceforge: http://sourceforge.net/projects/greenshot/ * * This program is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 1 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program. If not, see . */ using System; namespace Greenshot.Helpers { /// /// Description of GeometryHelper. /// public static class GeometryHelper { /// /// Finds the distance between two points on a 2D surface. /// /// The point on the x-axis of the first point /// The point on the x-axis of the second point /// The point on the y-axis of the first point /// The point on the y-axis of the second point /// public static int Distance2D(int x1, int y1, int x2, int y2) { //Our end result int result = 0; //Take x2-x1, then square it double part1 = Math.Pow(x2 - x1, 2); //Take y2-y1, then square it double part2 = Math.Pow(y2 - y1, 2); //Add both of the parts together double underRadical = part1 + part2; //Get the square root of the parts result = (int)Math.Sqrt(underRadical); //Return our result return result; } /// /// Calculates the angle of a line defined by two points on a 2D surface. /// /// The point on the x-axis of the first point /// The point on the x-axis of the second point /// The point on the y-axis of the first point /// The point on the y-axis of the second point /// public static double Angle2D(int x1, int y1, int x2, int y2) { return Math.Atan2(y2 - y1, x2 - x1) * 180 / Math.PI; } } }